Problem :
Game Time with Minutes
Adapted by Neilor Tonin, URI
Brazil
Timelimit: 1
Brazil
Read the start time and end time of a game, in hours and minutes (initial hour, initial minute, final hour, final minute). Then print the duration of the game, knowing that the game can begin in a day and finish in another day,
Obs.: With a maximum game time of 24 hours and the minimum game time of 1 minute.
Input
Four integer numbers representing the start and end time of the game.
Output
Print the duration of the game in hours and minutes, in this format: “O JOGO DUROU XXX HORA(S) E YYY MINUTO(S)” . Which means: the game lasted XXX hour(s) and YYY minutes.
| Sample Input | Sample Output |
| 7 8 9 10 | O JOGO DUROU 2 HORA(S) E 2 MINUTO(S) |
| 7 7 7 7 | O JOGO DUROU 24 HORA(S) E 0 MINUTO(S) |
| 7 10 8 9 | O JOGO DUROU 0 HORA(S) E 59 MINUTO(S) |
Solution:
#include <iostream>#include <stdio.h>using namespace std;int main(){ int a, b, c, d; cin >> a; cin >> b; cin >> c; cin >> d; int inicio = a*60 + b; int final = c*60 + d; int duracao = 0; if(a <= c){ duracao = final - inicio; if(duracao == 0) printf("O JOGO DUROU %d HORA(S) E %d MINUTO(S)\n",24,duracao%60); else printf("O JOGO DUROU %d HORA(S) E %d MINUTO(S)\n",(duracao - duracao%60)/60,duracao%60); }else{ duracao = (24*60 - inicio) + final; printf("O JOGO DUROU %d HORA(S) E %d MINUTO(S)\n",(duracao - duracao%60)/60,duracao%60); } return 0; }
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