Problem :
Triangle Types
Adapted by Neilor Tonin, URI
Brazil
Timelimit: 1
Brazil
Read 3 double numbers (A, B and C) representing the sides of a triangle and arrange them in decreasing order, so that the side A is the biggest of the three sides. Next, determine the type of triangle that they can make, based on the following cases always writing an appropriate message:
- if A ≥ B + C, write the message: NAO FORMA TRIANGULO
- if A2 = B2 + C2, write the message: TRIANGULO RETANGULO
- if A2 > B2 + C2, write the message: TRIANGULO OBTUSANGULO
- if A2 < B2 + C2, write the message: TRIANGULO ACUTANGULO
- if the three sides are the same size, write the message: TRIANGULO EQUILATERO
- if only two sides are the same and the third one is different, write the message: TRIANGULO ISOSCELES
Input
The input contains three double numbers, A (0 < A) , B (0 < B) and C (0 < C).
Output
Print all the classifications of the triangle presented in the input.
| Sample Inputs | Sample Outputs |
| 7.0 5.0 7.0 | TRIANGULO ACUTANGULO TRIANGULO ISOSCELES |
| 6.0 6.0 10.0 | TRIANGULO OBTUSANGULO TRIANGULO ISOSCELES |
| 6.0 6.0 6.0 | TRIANGULO ACUTANGULO TRIANGULO EQUILATERO |
| 5.0 7.0 2.0 | NAO FORMA TRIANGULO |
| 6.0 8.0 10.0 | TRIANGULO RETANGULO |
Solution:
#include<stdio.h>int main(){ double a[4], temp; int i , j; for(i=0; i<3; i++) scanf("%lf",&a[i]); for(i=0; i<3; i++) { for(j=i; j<3; j++) { if(a[0]<a[j]) { temp=a[i]; a[i]=a[j]; a[j]=temp; } } } if(a[0]>=a[1]+a[2]){ printf("NAO FORMA TRIANGULO\n"); exit(0); } if(a[0]*a[0]==((a[1]*a[1])+(a[2]*a[2]))) printf("TRIANGULO RETANGULO\n"); if(a[0]*a[0]>((a[1]*a[1])+(a[2]*a[2]))) printf("TRIANGULO OBTUSANGULO\n"); if(a[0]*a[0]<((a[1]*a[1])+(a[2]*a[2]))) printf("TRIANGULO ACUTANGULO\n"); if(a[0]==a[1] && a[1]==a[2]) printf("TRIANGULO EQUILATERO\n"); if((a[0]==a[1] && a[0]!=a[2]) || (a[1]==a[2] && a[1]!=a[0]) || (a[0]==a[2] && a[0]!=a[1])) printf("TRIANGULO ISOSCELES\n"); return 0;}
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